Steins;Gate and its sequel movie Steins;Gate: The Movie − Load Region of Déjà Vu

The lines of the tree trunk and lamppost shadows all converge toward where the sun is, if extended toward it.

I’m pretty sure that’s not true

Edit: I’ll concede the other points though

The tree on the right has that block missing in its shadow, the trees on the left are casting their shadows in a slightly different direction, and they guy on the dirt path’s shadow seems too dark and clear. Once you pointed out something was wrong, it’s hard not to see other mistakes.

why do people have this innate ability to underestimate what we might be capable of?

Because we can see what we’re currently capable of in terms of climate change, and the outlook is pretty bleak

why do you think its impossible for us to become masters of our own genome?

Because even in the best case scenario, this is dangerously close to eugenics

not getting off this rock means our species is doomed regardless of how ‘perfect’ we keep earth.

If we can’t keep earth livable, an entire self-regulating planet that’s been livable for hundreds of millions or billions of years, what are our chances of keeping anywhere else livable?

Only reason to be anti genocide is you being an Iranian agent.

What a thing to say. Really, just step back and look at the words you wrote.

Yeah, but have you considered the electoral college? For most people, their vote for president doesn’t matter.

It also didn’t help that it was one of the first $70 games when the norm was $60.

I really don’t think CSAM is a fake crime, but we can’t all be libertarians.

https://www.youtube.com/playlist?list=PLOBp3v-_cPa2f05inQWNrm0KMd6VHSgyc

Youtube says there are only 441 videos in the complete series, I’m sure you’ll find your cousin eventually.

Although it is weird, wikipedia and archive.org are telling me there should only be 65.

A decent number of titles I’ve seen on there don’t have DRM.

Which games on GOG do you think have DRM? GOG’s whole deal is they sell DRM-free games.

Wouldn’t you know it, there’s a wikipedia article for that. I personally have used 7digital and bandcamp, but qobuz has been mentioned several times in other comments and hdtracks seems like it might work after you create an account.

They might be the most common because they’re the easiest, but there are also still plenty of people actually paying for the games. I’ll never be convinced that piracy is an actual threat to making money. Piracy has never been easier, just see /c/piracy@lemmy.dbzer0.com for proof, and yet pretty much all forms of entertainmment are as profitable as ever.

(C )Any digital good that is advertised or offered to a person that the seller cannot revoke access to after the transaction, which includes making the digital good available at the time of purchase for permanent offline download to an external storage source to be used without a connection to the internet.

It shouldn’t be that hard, gog.com manages to do it

4chan anon who made significant contribution to a math problem in order to find the best way to watch an anime

Looks like this one https://en.wikipedia.org/wiki/Superpermutation based on the content of the wikipedia article

Given r=f(θ), we are generally not concerned with r′=f′(θ); that describes how fast r changes with respect to θ

You’re using the derivative of a polar equation as the basis for what a tangent line is. But as the textbook explains, that doesn’t give you a tangent line or describe the slope at that point. I never bothered defining what “tangent” means, but since this seems so important to you why don’t you try coming up with a reasonable definition?

I think we fundamentally don’t agree on what “tangent” means. You can use

x=f(θ)cosθ, y=f(θ)sinθ to compute dydx

as taken from the textbook, giving you a tangent line in the terms used in polar coordinates. I think your line of reasoning would lead to r=1 in polar coordinates being a line, even though it’s a circle with radius 1.

Given r=f(θ), we are generally not concerned with r′=f′(θ); that describes how fast r changes with respect to θ

I think this part from the textbook describes what you’re talking about

Instead, we will use x=f(θ)cosθ, y=f(θ)sinθ to compute dydx.

And this would give you the actual tangent line, or at least the slope of that line.

Polar Functions and dydx

We are interested in the lines tangent a given graph, regardless of whether that graph is produced by rectangular, parametric, or polar equations. In each of these contexts, the slope of the tangent line is dydx. Given r=f(θ), we are generally not concerned with r′=f′(θ); that describes how fast r changes with respect to θ. Instead, we will use x=f(θ)cosθ, y=f(θ)sinθ to compute dydx.

From the link above. I really don’t understand why you seem to think a tangent line in polar coordinates would be a circle.

A straight line in polar coordinates with the same tangent would be a circle.

I’m not sure that’s true. In non-euclidean geometry it might be, but aren’t polar coordinates just an alternative way of expressing cartesian?

Looking at a libre textbook, it seems to be showing that a tangent line in polar coordinates is still a straight line, not a circle.

The tangent of all points along the line equal that line